GAT Qudrat Math

Provider · Qiyas — National Center for Assessment Section · Quantitative (الكمّي) Chapters · 8 Explorers · 3 interactive

Test format & strategy

GAT Qudrat — Quantitative Format & Strategy No calculator

The General Aptitude Test (GAT — القدرات العامة, "Qudrat") is administered by Qiyas. Alongside a verbal section it has a quantitative section that measures reasoning with numbers rather than memorised content.

What to expect

Questions are multiple choice and are answered without a calculator, so speed and clean mental methods matter as much as the mathematics. The quantitative material draws on arithmetic, algebra, geometry and data — at roughly a middle- to early-secondary level — plus a distinctive quantitative-comparison question type covered in Chapter 5.

GAT Qudrat — Quantitative Section Map

Chapter	Topics tested	Typical share
1 — Arithmetic	Operations, fractions, LCM/GCD, estimation	~20%
2 — Ratios & %	Part:whole ratios, percentage change, proportions	~15%
3 — Algebra	Linear equations, systems, expansion, substitution	~20%
4 — Geometry	Perimeter, area, angles, triangles, circles	~15%
5 — QC Questions	Compare Quantity A vs B; 4-choice response	~15%
6 — Sequences	Arithmetic/geometric nth term, visual patterns	~10%
7 — Data & Probability	Mean, median, mode; table reading; basic probability	~5%

Format: Multiple choice, no calculator. Questions are in Arabic. Key strategy: estimate first, test special values on QC questions.

Format

multiple choice

Calculator

not permitted

Skills

arithmetic · algebra · geometry · data

Signature

quantitative comparisons

▲ Three habits that save time

Estimate before computing; keep fractions instead of converting to decimals where possible; and on comparison questions, test convenient values (such as $0$ , $1$ , and a negative) before committing to an answer.

Typical domain weightings on the GAT Qudrat quantitative section. Comparison and logical reasoning represent the largest individual share (~25%).

⚠️ Common Traps — Mental Math & Negative Numbers

No calculator is allowed on Qudrat: Always look for factoring, cancellation, or estimation before doing long arithmetic. Also beware of sign rules: $(-x)^2 = x^2$ is always positive, but $-x^2$ is negative!

A student answers 36 out of 45 questions correctly. What percentage is that?

\frac{36}{45} = \frac{4}{5} = \frac{4 \times 20}{5 \times 20} = \frac{80}{100} = 80\%.

A test has 120 questions. A student finishes 75% of the test in 90 minutes. At this steady rate, how many minutes will the remaining questions take?

The remaining portion is $100\% - 75\% = 25\%$ , which is exactly $\frac{1}{3}$ of the 75% completed. Therefore, the remaining time is $\frac{90}{3} = 30$ minutes.

📝 Chapter Quiz

Questions Level

Arithmetic & Number Sense

GAT Qudrat — Quantitative Ch.1 Arithmetic No calculator

The foundation: order of operations, fractions, factors and multiples, and quick estimation.

▲ Reference — Number facts

Follow order of operations (brackets, powers, ×÷, +−). To compare fractions, cross-multiply or use a common denominator. A number's prime factorisation reveals its factors, GCD and LCM.

Order

brackets → powers → ×÷ → +−

Compare

\tfrac{a}{b}\ \text{vs}\ \tfrac{c}{d}\Rightarrow ad\ \text{vs}\ bc

Percent

p\%\ \text{of}\ N=\tfrac{p}{100}N

Average

\dfrac{\text{sum}}{\text{count}}

Worked example 1.A

Which is larger, $\tfrac23$ or $\tfrac35$ ? Cross-multiply: $2\times5=10$ versus $3\times3=9$ . Since $10>9$ , $\tfrac23>\tfrac35.$

Worked example 1.B

Find $15\%$ of $200$ . $\tfrac{15}{100}\times200=30.$

Fraction operations visualized on a number line using the least common denominator 18.

\frac{15}{18} + \frac{14}{18} - \frac{6}{18} = \frac{23}{18} = 1\frac{5}{18}

⚠️ Common Traps — Order of Operations & Fraction Denominators

Adding fractions requires a common denominator: Never add numerators and denominators directly ( $\frac{a}{b} + \frac{c}{d} \neq \frac{a+c}{b+d}$ ). Also remember the order of operations: multiplication and division precede addition and subtraction: $5 + 5 \times 5 = 5 + 25 = 30$ , NOT 50!

What is

\dfrac{5}{6}+\dfrac{7}{9}-\dfrac{1}{3}

Least common denominator = 18:

\frac{15}{18} + \frac{14}{18} - \frac{6}{18} = \frac{15 + 14 - 6}{18} = \frac{23}{18} = 1\frac{5}{18}.

Evaluate the numerical expression

\dfrac{2^5 \times 3^3}{6^2 \times 2}

without using a calculator.

Factor $6^2 = (2 \times 3)^2 = 2^2 \times 3^2$ . The denominator is $2^2 \times 3^2 \times 2 = 2^3 \times 3^2$ .

Divide powers: $\frac{2^5 \times 3^3}{2^3 \times 3^2} = 2^{5-3} \times 3^{3-2} = 2^2 \times 3^1 = 4 \times 3 = 12.$

📝 Chapter Quiz

Questions Level

Ratios, Proportion & Percentages

GAT Qudrat — Quantitative Ch.2 Ratios & % No calculator

Ratios share a quantity in parts; percentages express change. Both appear constantly on the test, often disguised in word problems.

▲ Reference — Ratio & percent

To split a total in ratio $a:b$ , there are $a+b$ equal parts. Percentage change is $\dfrac{\text{new}-\text{old}}{\text{old}}\times100\%$ . A rise of $p\%$ then a fall of $p\%$ does not return to the start.

Adjust the two parts of the ratio below and watch how a total of 120 divides between them.

⊙ Explorer · Sharing in a ratiointeractive

The split of the total by the current ratio
quantity	value

Part a = 2

Part b = 3

first share—

second share—

Each part is $\tfrac{120}{a+b}$ ; the shares are $a$ and $b$ of those parts.

Now fix an original value of 80 and slide the new value to read the percentage change directly.

⊙ Explorer · Percentage changeinteractive

Original and new values, and the percent change
quantity	value

New value = (original 80) 100

percentage change—

$\dfrac{\text{new}-80}{80}\times100\%$ . Equal bars mean $0\%$ change.

\dfrac{\text{total}}{a+b}

per part

% change

\dfrac{\text{new}-\text{old}}{\text{old}}\times100

Increase

\times(1+\tfrac{p}{100})

Decrease

\times(1-\tfrac{p}{100})

Worked example 2.A

Share $150$ in the ratio $2:3$ . Five parts, each $30$ : $60\ \text{and}\ 90.$

Worked example 2.B

A price of $100$ rises $10\%$ , then falls $10\%$ . Find the final price. $100\times1.1\times0.9=99.$

Part-to-part ratio 3:5 with 40 girls. Each ratio part represents

40 / 5 = 8

students, giving 24 boys and 64 total students.

⚠️ Common Traps — Part-to-Part vs. Part-to-Whole Ratios

Don't confuse ratio parts with totals: If the ratio of boys to girls is $3:5$ , the total parts is $3 + 5 = 8$ , so boys represent $\frac{3}{8}$ of the class, NOT $\frac{3}{5}$ ! Also, a percentage increase followed by the same percentage decrease never returns to the starting value: a 20% increase followed by a 20% decrease yields $1.20 \times 0.80 = 0.96$ (a net 4% decrease).

A class has boys to girls in the ratio 3:5. If there are 40 girls, how many students in total?

5 parts = 40 => 1 part = 8. Total parts = 3 + 5 = 8 parts. Total students = 8 * 8 = 64.

An item's price is reduced by 25% to 150 SAR. What was its original price before the discount?

After a 25% discount, the customer pays $100\% - 25\% = 75\% = \frac{3}{4}$ of the original price.

$\frac{3}{4} \times \text{Original} = 150 \implies \text{Original} = 150 \times \frac{4}{3} = 200 \text{ SAR}.$

📝 Chapter Quiz

Questions Level

Algebra Essentials

GAT Qudrat — Quantitative Ch.3 Algebra No calculator

Linear equations, simple systems, expansion and substitution — the algebra that the quantitative section relies on.

▲ Reference — Working with unknowns

Solve a linear equation by isolating the variable. A system of two equations can be solved by elimination or substitution. Expand $(x+a)(x+b)=x^2+(a+b)x+ab$ .

Linear

ax+b=c

Expand

(x+a)(x+b)

System

eliminate or substitute

Powers

a^{m}a^{n}=a^{m+n}

Worked example 3.A

Solve $2x+5=17$ . $2x=12,\qquad x=6.$

Worked example 3.B

If $x+y=10$ and $x-y=4$ , find $x$ . Add the equations: $2x=14$ . $x=7.$

Graphical intersection of the two linear equations

2x + y = 11

and

x - y = 1

at the unique solution point

(4, 3)

⚠️ Common Traps — Distributing Negative Signs & Binomial Squares

Distribute negative signs to all terms inside parentheses: $-(x - 4) = -x + 4$ , NOT $-x - 4$ . Also remember that $(x + y)^2 \neq x^2 + y^2$ ; the middle term $2xy$ must not be omitted: $(x + y)^2 = x^2 + 2xy + y^2$ .

Solve the linear system:

2x + y = 11

and

x - y = 1

Add the two equations to eliminate y: 3x = 12 => x = 4. Substitute x = 4 into x - y = 1 => 4 - y = 1 => y = 3. Solution: (x, y) = (4, 3).

x + y = 7

and

xy = 10

, find the value of

x^2 + y^2

without solving for

x

and

y

individually.

Use the algebraic identity $(x + y)^2 = x^2 + 2xy + y^2$ :

x^2 + y^2 = (x + y)^2 - 2xy = 7^2 - 2(10) = 49 - 20 = 29.

📝 Chapter Quiz

Questions Level

Geometry & Measurement

GAT Qudrat — Quantitative Ch.4 Geometry No calculator

Angles, triangles, area, perimeter and volume — applied quickly, usually without a calculator.

▲ Reference — Shapes & space

Triangle angles sum to $180^{\circ}$ ; a quadrilateral to $360^{\circ}$ . Pythagoras: $a^2+b^2=c^2$ . Circle area $\pi r^2$ , circumference $2\pi r$ .

Triangle

angles

=180^{\circ}

Rectangle

A=bh

Circle

A=\pi r^{2}

Pythagoras

a^{2}+b^{2}=c^{2}

Worked example 4.A

A right triangle has legs $6$ and $8$ . Find the hypotenuse. $\sqrt{6^{2}+8^{2}}=10.$

Worked example 4.B

Find the area of a circle with $r=7$ , taking $\pi=\tfrac{22}{7}$ . $\tfrac{22}{7}\times49=154.$

Rectangle with perimeter

P = 2[(2x+3) + (x+1)] = 38

cm, yielding

x = 5

, length 13 cm, width 6 cm, and area

78\text{ cm}^2

⚠️ Common Traps — Perimeter vs. Area Scaling

Linear scale vs. area scale: If the dimensions of any shape are doubled, its perimeter doubles (scale factor 2), but its area is multiplied by $2^2 = 4$ ! For circles, remember area is $\pi r^2$ with radius $r$ , NOT diameter $d$ .

A rectangle has length

(2x+3)

cm and width

(x+1)

cm with perimeter 38 cm. Find the area.

2[(2x+3) + (x+1)] = 38 => 3x + 4 = 19 => 3x = 15 => x = 5. Length = 13 cm, Width = 6 cm. Area = 13 * 6 = 78 cm².

A right triangle has a hypotenuse of 15 cm and one leg of 9 cm. Find its area in cm².

By the Pythagorean theorem: $\text{Other leg} = \sqrt{15^2 - 9^2} = \sqrt{225 - 81} = \sqrt{144} = 12 \text{ cm}.$ $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 9 \times 12 = 54 \text{ cm}^2.$

📝 Chapter Quiz

Questions Level

Quantitative Comparisons

GAT Qudrat — Quantitative Ch.5 QC Questions No calculator

The question type most associated with Qudrat: two quantities, A and B, and a single decision to make.

● The four responses

Choose: A > B, A < B, A = B, or cannot be determined — the last when the relationship changes depending on unknown values. Always test convenient numbers before deciding.

Here $A=2x$ and $B=x+3$ . Slide $x$ : notice the order of A and B flips, so with $x$ unknown the honest answer is "cannot be determined".

⊙ Explorer · A vs Binteractive

Quantity A and B at the current x, and how the relation changes across x
x	A = 2x	B = x + 3	relation

x

= 1

A = 2x—

B = x + 3—

relationship—

They are equal at $x=3$ ; to the left $B$ leads, to the right $A$ leads.

Worked example 5.A

A: $25\%$ of $80$ . B: $20$ . Compare. $25\%$ of $80=20$ , so $A=B.$

Worked example 5.B

A: $x$ . B: $x^{2}$ , for a real number $x$ . Compare. If $x=\tfrac12$ then $B<A$ ; if $x=2$ then $B>A$ . Therefore $\text{cannot be determined.}$

▲ Quantitative comparison strategy

Each QC question gives two quantities, A and B. You choose: A>B, B>A, A=B, or cannot be determined. Plug in special values (0, 1, −1, fractions) to test.

Strategy 1

Simplify both columns algebraically before comparing

Strategy 2

Plug in 0, 1, −1, ½ to check if relationship is constant

Strategy 3

If a variable could make either column larger: "cannot determine"

Geometry tip

Draw a diagram; do not assume figures are to scale

Worked example

Column A: $x^2$ . Column B: $x$ . Compare. If $x=2$ : $4>2$ . If $x=\frac{1}{2}$ : $\frac{1}{4}<\frac{1}{2}$ . If $x=0$ : equal. → Cannot be determined.

Critical testing values for quantitative comparisons. Testing negative numbers, zero, and fractions between 0 and 1 uncovers hidden case reversals.

⚠️ Common Traps — Variables with Unknown Signs in Comparisons

Always test multiple test cases when variables are unconstrained: Never test only positive integers! Test $x = 0$ , $x = 1$ , $x = -1$ , and a fraction like $x = \frac{1}{2}$ . For instance, if $x < 1$ , is $x^2 > x$ ? For $x = -2$ , $4 > -2$ (true); but for $x = 0.5$ , $0.25 < 0.5$ (false), making the comparison (D) "Cannot be determined".

Quantity A:

(x-3)^2

Quantity B:

x^2-6x+9

for any real

x

. Compare.

Expand Quantity A: (x - 3)² = x² - 6x + 9. The two quantities are algebraically identical for all real values of x: A = B.

Given

x > 1

: Quantity A:

x^3

Quantity B:

x^2

. Compare.

Since $x > 1$ , we can divide both quantities by the strictly positive quantity $x^2$ : $\frac{x^3}{x^2} = x, \qquad \frac{x^2}{x^2} = 1.$ Since $x > 1$ , Quantity A is strictly greater than Quantity B.

📝 Chapter Quiz

Questions Level

Sequences & Patterns

GAT Qudrat — Quantitative Ch.6 Sequences No calculator

Spotting the rule behind a list of numbers — arithmetic, geometric, or a quick visual pattern.

▲ Reference — Two key sequences

Arithmetic adds a constant difference $d$ : the $n$ th term is $a+(n-1)d$ . Geometric multiplies by a constant ratio $r$ : the $n$ th term is $ar^{\,n-1}$ .

Arithmetic

a+(n-1)d

Geometric

ar^{\,n-1}

First n integers

\tfrac{n(n+1)}{2}

Look for

difference or ratio

Worked example 6.A

Find the next term: $2,\,4,\,8,\,16,\ldots$ Geometric, ratio $2$ : $32.$

Worked example 6.B

Find the $10$ th term of $5,\,8,\,11,\ldots$ $5+9\times3=32.$

Worked example 6.C

The sequence $1,4,9,16,25,\ldots$ What is the 8th term? These are perfect squares: $n^2.$ So the 8th term is $8^2=64.$

Visualizing the first four terms of the arithmetic progression with first term

a = 7

and common difference

d = 5

: 7, 12, 17, 22.

⚠️ Common Traps — Off-by-One Counting in Integer Sequences

Counting inclusive numbers between bounds: The count of integers from $A$ to $B$ inclusive is $B - A + 1$ , NOT $B - A$ ! For example, the count of integers from 10 to 20 inclusive is $20 - 10 + 1 = 11$ , not 10. For arithmetic sequences, term count is $\frac{\text{Last} - \text{First}}{\text{Common Difference}} + 1$ .

An arithmetic sequence has first term 7 and common difference 5. Which term equals 82?

7 + (n - 1)*5 = 82 => (n - 1)*5 = 75 => n - 1 = 15 => n = 16. The 16th term.

How many multiples of 4 are there between 15 and 95?

The smallest multiple of 4 greater than 15 is 16. The largest multiple less than 95 is 92.

$\text{Number of terms} = \frac{\text{Last} - \text{First}}{\text{Step}} + 1 = \frac{92 - 16}{4} + 1 = \frac{76}{4} + 1 = 19 + 1 = 20.$

📝 Chapter Quiz

Questions Level

Data Analysis & Probability

GAT Qudrat — Quantitative Ch.7 Data No calculator

Reading values from tables and charts, summarising with mean, median and mode, and computing simple probabilities.

▲ Reference — Summaries & chance

Mean is the total divided by the count; the median is the middle of the ordered list; the mode is the most frequent value. Probability of an event is $\dfrac{\text{favourable}}{\text{total}}$ .

Mean

\dfrac{\text{sum}}{\text{count}}

Median

middle (ordered)

Mode

most frequent

Probability

\dfrac{\text{favourable}}{\text{total}}

Worked example 7.A

Find the mean of $4,\,6,\,8,\,10,\,12$ . $\frac{40}{5}=8.$

Worked example 7.B

A bag holds 2 red and 3 green balls. Find $P(\text{red})$ . $\frac{2}{5}.$

Age frequency distribution showing mode = 14 (frequency 3). When ordered: 14, 14, 14, 15, 16, 17, 18, median = 15 (middle 4th value).

⚠️ Common Traps — Ordering Before Finding Median

Always sort data before finding the median: The median is the middle value of a SORTED dataset. Picking the middle value of unsorted data is an immediate error. Also note that extreme outliers distort the mean heavily, whereas the median remains stable.

Ages of 7 students: 14, 16, 14, 17, 15, 14, 18. Find mean, median, and mode.

Ordered list: 14, 14, 14, 15, 16, 17, 18. Mean = (14+14+14+15+16+17+18)/7 = 108/7 ≈ 15.4. Median = 15 (4th value). Mode = 14 (appears 3 times).

The average score of 5 students on a test is 82. When a 6th student's score is included, the new average becomes 84. What did the 6th student score?

Total sum of first 5 scores = $5 \times 82 = 410$ .

Total sum of all 6 scores = $6 \times 84 = 504$ .

Score of the 6th student = $504 - 410 = 94$ .

📝 Chapter Quiz

Questions Level

Word Problems & Reasoning

GAT Qudrat — Quantitative Ch.8 Word Problems No calculator

Many Qudrat items are short word problems testing translation into arithmetic or algebra and logical deduction.

▲ Reference — Strategy

Translate the words into an equation, work backwards from the answer choices, and estimate to eliminate. Always check units and whether the answer is reasonable.

Translate

to an equation

Backsolve

test the choices

Estimate

& eliminate

Check

units & sense

Worked example 8.A

A number increased by $6$ equals $20$ . Find the number. $x+6=20\Rightarrow x=14.$

Worked example 8.B

A car travels 240 km in 3 hours. At the same speed, how far in 5 hours? Speed $=240/3=80$ km/h. Distance $=80\times5=400$ km.

Financial allocation breakdown: earning 1200 SAR/month for 8 months gives 9600 SAR. Saving 25% yields 2400 SAR. Subtracting device cost 1800 SAR leaves 600 SAR.

⚠️ Common Traps — Average Speed & Combined Work Rates

Average speed is NOT the arithmetic average of speeds: If you travel to a destination at 60 km/h and return at 40 km/h, the average speed is $\frac{\text{Total Distance}}{\text{Total Time}} = 48$ km/h, NOT $\frac{60+40}{2} = 50$ ! For combined work problems, always add the rates per unit time ( $\frac{1}{t_1} + \frac{1}{t_2}$ ), not the times.

Ahmad earns 1200 SAR/month and saves

\frac{1}{4}

of it. After 8 months he buys a device for 1800 SAR. How much remains?

Monthly savings = 1200 * (1/4) = 300 SAR. Total saved over 8 months = 300 * 8 = 2400 SAR. Remaining balance = 2400 - 1800 = 600 SAR.

Worker A can complete a task alone in 6 hours, while Worker B can complete the same task in 3 hours. How many hours will it take them working together?

Combined hourly rate = $\frac{1}{6} + \frac{1}{3} = \frac{1}{6} + \frac{2}{6} = \frac{3}{6} = \frac{1}{2}$ of the job per hour.

Total time needed = $\frac{1}{1/2} = 2$ hours.

📝 Chapter Quiz

Questions Level

Practice set

Fifty exam-style problems across all chapters — including a block of quantitative comparisons — tagged by difficulty. Click any problem for a full worked solution.

Find $15\%$ of $200$ .

Basic

\tfrac{15}{100}\times200=30.

Find $\tfrac35$ of $60$ .

Basic

\tfrac35\times60=36.

Compute $0.25\times80$ .

Basic

\tfrac14\times80=20.

Which is larger, $\tfrac23$ or $\tfrac35$ ?

Intermediate

Cross-multiply: $2\cdot5=10>3\cdot3=9$ .

\tfrac23>\tfrac35.

Find the remainder when $47$ is divided by $6$ .

Intermediate

$6\times7=42$ , remainder $47-42$ :

5.

Find the average of $12,\,18,\,30$ .

Intermediate

\frac{60}{3}=20.

Evaluate $7^{2}-3^{2}$ .

Intermediate

49-9=40.

If $5x=35$ , find $x^{2}$ .

Advanced

$x=7$ , so $x^{2}=49$ :

49.

Simplify the ratio $8:12$ .

Basic

8:12=2:3.

Increase $50$ by $20\%$ .

Intermediate

50\times1.2=60.

Decrease $90$ by $10\%$ .

Intermediate

90\times0.9=81.

Share $150$ in the ratio $2:3$ .

Intermediate

Five parts, each $30$ :

60\ \text{and}\ 90.

If $3$ pens cost $12$ , what do $5$ pens cost?

Intermediate

One pen costs $4$ :

5\times4=20.

What percentage is $18$ of $72$ ?

Intermediate

\frac{18}{72}=\tfrac14=25\%.

A price of $100$ rises $10\%$ , then falls $10\%$ . Find the net percentage change.

Advanced

$100\to110\to99$ :

-1\%.

$40\%$ of a number is $32$ . Find the number.

Intermediate

\frac{32}{0.4}=80.

Solve $2x+5=17$ .

Basic

2x=12,\qquad x=6.

Simplify $3a+2a-a$ .

Basic

4a.

If $x+y=10$ and $x-y=4$ , find $x$ .

Intermediate

Add: $2x=14$ :

x=7.

Solve $\tfrac{x}{3}=9$ .

Intermediate

x=27.

Find the value of $3x-2$ when $x=4$ .

Intermediate

12-2=10.

Solve $2(x-3)=8$ .

Intermediate

$x-3=4$ :

x=7.

If $a^{2}=49$ and $a<0$ , find $a$ .

Advanced

a=-7.

Expand $(x+2)(x+3)$ .

Intermediate

x^{2}+5x+6.

Solve the inequality $x+4>9$ .

Intermediate

x>5.

If $2^{x}=16$ , find $x$ .

Advanced

2^{4}=16\Rightarrow x=4.

Two angles of a triangle are $50^{\circ}$ and $60^{\circ}$ . Find the third.

Basic

180^{\circ}-110^{\circ}=70^{\circ}.

Find the area of a rectangle $7\times6$ .

Intermediate

7\times6=42.

Find the perimeter of a square of side $9$ .

Intermediate

4\times9=36.

Find the area of a circle with $r=7$ , taking $\pi=\tfrac{22}{7}$ .

Intermediate

\tfrac{22}{7}\times49=154.

A right triangle has legs $6$ and $8$ . Find the hypotenuse.

Intermediate

\sqrt{36+64}=10.

Find the sum of the interior angles of a quadrilateral.

Intermediate

360^{\circ}.

Find the volume of a cube of side $5$ .

Advanced

5^{3}=125.

Two angles lie on a straight line; one is $130^{\circ}$ . Find the other.

Intermediate

180^{\circ}-130^{\circ}=50^{\circ}.

Comparison. A: $25\%$ of $80$ . B: $20$ .

Intermediate

$25\%$ of $80=20$ :

A=B.

Comparison. A: $3^{2}$ . B: $2^{3}$ .

Intermediate

$9$ versus $8$ :

A>B.

Comparison. A: the average of $10$ and $20$ . B: $15$ .

Intermediate

$\tfrac{10+20}{2}=15$ :

A=B.

Comparison. A: $x$ . B: $x^{2}$ , for a real number $x$ .

Advanced

$x=\tfrac12\Rightarrow B<A$ ; $x=2\Rightarrow B>A$ :

\text{cannot be determined.}

Comparison. A: $\tfrac12$ . B: $0.4$ .

Intermediate

$0.5>0.4$ :

A>B.

Comparison. A: perimeter of a square of side $4$ . B: perimeter of a $3\times5$ rectangle.

Advanced

$16$ versus $2(3+5)=16$ :

A=B.

Comparison. A: $2x+1$ . B: $2x+3$ .

Advanced

B exceeds A by $2$ for every $x$ :

A<B.

Comparison. A: $(-3)^{2}$ . B: $-(3^{2})$ .

Advanced

$9$ versus $-9$ :

A>B.

Find the next term: $2,\,4,\,8,\,16,\ldots$

Basic

32.

Find the next term: $3,\,7,\,11,\,15,\ldots$

Intermediate

Add $4$ :

19.

Find the $10$ th term of $5,\,8,\,11,\ldots$

Intermediate

5+9\times3=32.

Find $1+2+3+\cdots+10$ .

Advanced

\frac{10\times11}{2}=55.

Find the mean of $4,\,6,\,8,\,10,\,12$ .

Basic

\frac{40}{5}=8.

Find the median of $3,\,9,\,5,\,1,\,7$ .

Intermediate

Ordered $1,3,5,7,9$ ; middle:

5.

A fair die is rolled. Find $P(\text{result} > 4)$ .

Intermediate

Favourable: $5,6$ :

\frac{2}{6}=\tfrac13.

A bag holds 2 red and 3 green balls. Find $P(\text{red})$ .

Advanced

\frac{2}{5}.

✎

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Full official exam paper

Based on the Saudi GAT Qudrat exam: 52 quantitative questions in 52 minutes. Includes standard MCQ and Quantitative Comparison items (Arabic/English bilingual). No calculator.

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Worksheet Library

8 original ClipSAT worksheets with full answer keys, each available in English and Arabic — free to download and print.

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GAT Qudrat Math

Test format & strategy

Arithmetic & Number Sense

Ratios, Proportion & Percentages

Algebra Essentials

Geometry & Measurement

Quantitative Comparisons

Sequences & Patterns

Data Analysis & Probability

Word Problems & Reasoning

Practice set

Test generator

Downloads

Qudrat notes & practice

Native Word packet

Past Papers & Official Tests

Worksheet Library

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GAT Qudrat Math

Test format & strategyشكل الاختبار والاستراتيجية

Arithmetic & Number Senseالحساب والحس العددي

Ratios, Proportion & Percentagesالنسب والتناسب والمئويات

Algebra Essentialsأساسيات الجبر

Geometry & Measurementالهندسة والقياس

Quantitative Comparisonsالمقارنات الكمّية

Sequences & Patternsالمتتاليات والأنماط

Data Analysis & Probabilityتحليل البيانات والاحتمالات

Word Problems & Reasoningالمسائل اللفظية والاستدلال

Practice set

Test generator

Downloads

Qudrat notes & practiceملاحظات وتدريبات القدرات

Native Word packet

Past Papers & Official Tests

Worksheet Library

Mock Exam

Test format & strategy

Arithmetic & Number Sense

Ratios, Proportion & Percentages

Algebra Essentials

Geometry & Measurement

Quantitative Comparisons

Sequences & Patterns

Data Analysis & Probability

Word Problems & Reasoning

Qudrat notes & practice