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AS Level Mathematics

Boards · Cambridge / Edexcel Level · AS · Year 1 Chapters · 8 Explorers · 3 interactive
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About AS Level

🗺 Cambridge AS Level Mathematics 9709 — Syllabus Map

PaperClipSAT ChapterKey Topics
P1 Pure 1Algebra — Indices, Surds & QuadraticsLaws of indices, surds, completing the square, discriminant
Simultaneous Equations & InequalitiesLinear/nonlinear systems, modulus inequalities
Graphs & Transformationsy=f(x) transformations: translations, stretches, reflections
Coordinate GeometryLine segments, circles, intersection
Circular MeasureRadians, arc length, sector area, segment
TrigonometryExact values, identities, solving equations in given range
Series & Binomial TheoremAP/GP, sum to infinity, \((a+b)^n\) expansion
Differentiation & IntegrationGradient, tangent/normal, stationary points, definite integral, area
P1Functions: Composite & InverseDomain, range, \(fg\), \(f^{-1}\)
M1 MechanicsKinematicsSUVAT, velocity-time graphs, calculus kinematics
Forces & Equilibrium / Newton's LawsResultant, components, \(F=ma\), connected particles
Energy, Work & PowerKE, PE, work-energy principle, power
S1 StatisticsRepresentation of DataHistograms, cumulative freq., mean, variance, SD, box plots
Permutations & Combinations\(n!\), \(^nP_r\), \(^nC_r\), arrangement with restrictions
Discrete Random VariablesProbability distribution, \(E(X)\), \(\text{Var}(X)\)
Binomial Distribution\(X\sim B(n,p)\), cumulative probabilities, mean & variance
Normal Distribution\(X\sim N(\mu,\sigma^2)\), standardisation, inverse normal

AS Level Mathematics is the first year of the A Level, offered by boards such as Cambridge (9709) and Edexcel. It blends Pure Mathematics with an introduction to Statistics and Mechanics.

What it covers

The Pure core runs through indices and surds, quadratics, coordinate geometry, graphs and transformations, trigonometry, and the first ideas of differentiation and integration. Applied units add probability, data handling and kinematics.

Pure
algebra · geometry · calculus
Statistics
data · probability
Mechanics
kinematics · forces
Calculator
allowed (most papers)
▲ How to use this course

Each chapter pairs a reference panel with worked examples; the explorers make slope, transformations and the gradient idea visual. Finish with the 50-problem set, then export it as a worksheet.

📝 Chapter Quiz
1

Indices, Surds & Quadratics

📌 Algebra — Indices, Surds & Quadratics P1  ·  Laws of indices  ·  Surds  ·  Completing the square  ·  Discriminant & nature of roots

The laws of indices, simplifying and rationalising surds, and the full toolkit for quadratics — factorising, completing the square and the formula.

▲ Reference — Algebra core

\( a^{m}a^{n}=a^{m+n} \), \( a^{-n}=\tfrac{1}{a^{n}} \), \( a^{1/n}=\sqrt[n]{a} \). Quadratic formula \( x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a} \); the discriminant \( b^{2}-4ac \) fixes the number of real roots.

Indices
\( a^{m}a^{n}=a^{m+n} \)
Surds
\( \sqrt{ab}=\sqrt{a}\sqrt{b} \)
Completing square
\( (x+\tfrac{b}{2})^{2}-\tfrac{b^{2}}{4} \)
Discriminant
\( b^{2}-4ac \)
Worked example 1.A

Simplify \( \sqrt{12} \).

\[ \sqrt{4\cdot3}=2\sqrt{3}. \]

Worked example 1.B

Complete the square for \( x^{2}+4x \).

\[ (x+2)^{2}-4. \]

Solve \(2x^2-5x-3=0\) by completing the square.
\(2(x^2-\tfrac{5}{2}x)=3\Rightarrow2(x-\tfrac{5}{4})^2-2\cdot\tfrac{25}{16}=3\Rightarrow(x-\tfrac{5}{4})^2=\tfrac{73}{16}\). Hmm — actually factor: \((2x+1)(x-3)=0\Rightarrow x=-\tfrac{1}{2}\text{ or }x=3\).
📝 Chapter Quiz
2

Simultaneous Equations & Inequalities

📌 Simultaneous Equations & Inequalities P1  ·  Linear & non-linear systems  ·  Quadratic inequalities  ·  Modulus function

Solving linear and linear-with-quadratic systems, and linear and quadratic inequalities.

▲ Reference — Systems & inequalities

Solve a linear system by substitution or elimination; for a linear–quadratic pair, substitute the linear equation into the quadratic. A quadratic inequality is solved by finding the roots and testing the sign of each interval.

Linear system
substitute / eliminate
Linear–quadratic
substitute the line
Sign rule
flip \( \le \) when \( \div(-) \)
Quadratic ineq.
roots then test
Worked example 2.A

Solve \( x+y=5 \), \( x-y=1 \).

Add: \( 2x=6 \):

\[ x=3,\ y=2. \]

Worked example 2.B

Solve \( x^{2}-4<0 \).

Roots \( \pm2 \), curve below axis between them:

\[ -2<x<2. \]

Solve simultaneously: \(y=x^2-3\) and \(y=2x+1\).
\(x^2-3=2x+1\Rightarrow x^2-2x-4=0\Rightarrow x=1\pm\sqrt{5}\). Corresponding \(y\) values: \(y=2(1+\sqrt5)+1=3+2\sqrt5\) and \(y=3-2\sqrt5\).
📝 Chapter Quiz
3

Graphs & Transformations

📌 Graphs & Transformations P1  ·  Sketching curves  ·  \(f(x+a)\), \(f(ax)\), \(-f(x)\), \(f(-x)\)  ·  Identifying transformations

Sketching standard curves and applying translations, reflections and stretches.

▲ Reference — Transformations of \( y=f(x) \)

\( f(x)+a \) shifts up by \( a \); \( f(x-a) \) shifts right by \( a \); \( -f(x) \) reflects in the \( x \)-axis; \( af(x) \) stretches vertically by factor \( a \).

The grey curve is \( y=\sin x \); the indigo curve is \( y=\sin(x-h)+k \). Slide \( h \) and \( k \) to translate it.

⊙ Explorer · Translating a graphinteractive
translation (h, k)

Inside the function, \( x-h \) moves right; outside, \( +k \) moves up.

Up by a
\( f(x)+a \)
Right by a
\( f(x-a) \)
Reflect (x-axis)
\( -f(x) \)
Stretch
\( af(x) \)
Worked example 3.A

Describe \( y=(x-2)^{2} \) relative to \( y=x^{2} \).

It is a translation \( 2 \) units to the right.

Worked example 3.B

Describe \( y=-x^{2} \) relative to \( y=x^{2} \).

A reflection in the \( x \)-axis.

The graph of \(y=f(x)\) passes through \((2,5)\). State the coordinates of the corresponding point on \(y=f(2x)-3\).
Horizontal stretch by \(\tfrac{1}{2}\): \(x\) becomes \(1\). Vertical shift \(-3\): \(y\) becomes \(2\). Point: \((1,2)\).
📝 Chapter Quiz
4

Coordinate Geometry

📌 Coordinate Geometry P1  ·  Line equations  ·  Circle equation & properties  ·  Tangent to a circle

Straight lines — gradient, midpoint, distance and equations — and the equation of a circle.

▲ Reference — Lines & circles

Gradient \( m=\dfrac{y_2-y_1}{x_2-x_1} \); line \( y-y_1=m(x-x_1) \). A circle with centre \( (a,b) \) and radius \( r \) is \( (x-a)^{2}+(y-b)^{2}=r^{2} \).

Adjust gradient \( m \) and intercept \( b \) of \( y=mx+b \); the amber dots are the intercepts.

⊙ Explorer · Gradient & interceptsinteractive
gradient
y-intercept
x-intercept

Perpendicular gradients satisfy \( m_1m_2=-1 \).

Gradient
\( \dfrac{y_2-y_1}{x_2-x_1} \)
Line
\( y-y_1=m(x-x_1) \)
Distance
\( \sqrt{\Delta x^{2}+\Delta y^{2}} \)
Circle
\( (x-a)^{2}+(y-b)^{2}=r^{2} \)
Worked example 4.A

Find the gradient through \( (1,2) \) and \( (4,11) \).

\[ \frac{11-2}{4-1}=3. \]

Worked example 4.B

State the centre of \( (x-2)^{2}+(y+3)^{2}=25 \).

\[ (2,\,-3). \]

A circle has centre \((3,-1)\) and passes through \((7,2)\). Find its equation.
Radius \(r=\sqrt{(7-3)^2+(2+1)^2}=\sqrt{16+9}=5\). Equation: \((x-3)^2+(y+1)^2=25\).
📝 Chapter Quiz
5

Trigonometry

📌 Trigonometry P1  ·  Exact trig values  ·  \(\sin^2\theta+\cos^2\theta=1\)  ·  Solving trig equations in a range

Exact values, the identity linking sine and cosine, and solving simple trigonometric equations.

▲ Reference — Trig essentials

\( \sin^{2}\theta+\cos^{2}\theta=1 \) and \( \tan\theta=\dfrac{\sin\theta}{\cos\theta} \). Exact values: \( \sin30^{\circ}=\tfrac12 \), \( \cos30^{\circ}=\tfrac{\sqrt3}{2} \), \( \sin60^{\circ}=\tfrac{\sqrt3}{2} \). The sine and cosine curves have period \( 360^{\circ} \).

Identity
\( \sin^{2}\theta+\cos^{2}\theta=1 \)
Tangent
\( \tfrac{\sin\theta}{\cos\theta} \)
Exact
\( \sin60^{\circ}=\tfrac{\sqrt3}{2} \)
Period
\( 360^{\circ} \)
Worked example 5.A

Solve \( \sin\theta=\tfrac12 \) for \( 0^{\circ}\le\theta\le180^{\circ} \).

\[ \theta=30^{\circ},\ 150^{\circ}. \]

Worked example 5.B

State the exact value of \( \sin60^{\circ} \).

\[ \tfrac{\sqrt3}{2}. \]

Solve \(2\sin^2\theta-\sin\theta-1=0\) for \(0°\leq\theta\leq360°\).
Factor: \((2\sin\theta+1)(\sin\theta-1)=0\Rightarrow\sin\theta=-\tfrac{1}{2}\) or \(\sin\theta=1\). Solutions: \(\theta=90°,210°,330°\).
📝 Chapter Quiz
6

Differentiation & Integration

📌 Differentiation & Integration P1  ·  Gradient & stationary points  ·  Tangent & normal  ·  Definite integral & area under curve

The gradient of a curve from first principles, the power rule for differentiation, and reversing it to integrate.

▲ Reference — The power rule

\( \dfrac{d}{dx}x^{n}=nx^{n-1} \); the gradient at a point is the value of \( \tfrac{dy}{dx} \) there. Integration reverses this: \( \displaystyle\int x^{n}\,dx=\dfrac{x^{n+1}}{n+1}+C \) for \( n\neq-1 \).

The amber line is a secant from \( x=1 \) to \( x=1+h \) on \( y=x^{2} \). Shrink \( h \) and watch its slope approach the tangent gradient, \( 2 \).

⊙ Explorer · Secant → tangentinteractive
secant gradient

The secant gradient is \( 2+h \); as \( h\to0 \) it tends to the tangent gradient \( 2 \).

Differentiate
\( nx^{n-1} \)
Gradient
value of \( \tfrac{dy}{dx} \)
Integrate
\( \tfrac{x^{n+1}}{n+1}+C \)
Definite
\( F(b)-F(a) \)
Worked example 6.A

Differentiate \( y=x^{2}+3x \).

\[ \frac{dy}{dx}=2x+3. \]

Worked example 6.B

Evaluate \( \displaystyle\int_{0}^{1} 2x\,dx \).

\[ \left[x^{2}\right]_{0}^{1}=1. \]

Find the equation of the normal to the curve \(y=x^3-4x\) at the point where \(x=2\).
\(y(2)=8-8=0\). \(y'=3x^2-4\Rightarrow y'(2)=8\). Normal gradient \(=-\tfrac{1}{8}\). Equation: \(y=-\tfrac{1}{8}(x-2)\Rightarrow8y+x=2\).
📝 Chapter Quiz
7

Statistics & Probability

📌 Statistics & Probability S1  ·  Basic probability  ·  Conditional probability  ·  Tree diagrams  ·  Venn diagrams

Summarising data with averages and spread, and the probability of simple events.

▲ Reference — Data & chance

Mean is total over count; the median is the middle of the ordered data; range is largest minus smallest. Probability \( =\dfrac{\text{favourable}}{\text{total}} \).

Mean
\( \dfrac{\sum x}{n} \)
Median
middle value
Range
max − min
Probability
\( \dfrac{\text{fav}}{\text{total}} \)
Worked example 7.A

Find the mean of \( 2,\,4,\,6,\,8 \).

\[ \frac{20}{4}=5. \]

Worked example 7.B

Find the median of \( 3,\,7,\,9,\,12,\,20 \).

\[ 9. \]

Events \(A\) and \(B\) are such that \(P(A)=0.4\), \(P(B)=0.5\), \(P(A\cup B)=0.7\). Find \(P(A\cap B)\) and state whether \(A\) and \(B\) are independent.
\(P(A\cap B)=0.4+0.5-0.7=0.2\). For independence: \(P(A)\cdot P(B)=0.2=P(A\cap B)\) ✓. \(A\) and \(B\) are independent.
📝 Chapter Quiz
8

Functions: Composite & Inverse

📌 Functions: Composite & Inverse P1  ·  Domain & range  ·  Composite \(fg(x)\)  ·  Inverse \(f^{-1}(x)\)  ·  Modulus function

Beyond graphs, AS treats functions formally — domain, range, composition and inverses.

▲ Reference — Functions

\( fg(x)=f(g(x)) \). The inverse \( f^{-1} \) reverses \( f \) and reflects its graph in the line \( y=x \); the range of \( f \) is the domain of \( f^{-1} \).

Composite
\( fg(x) \)
Inverse
swap & solve
Reflection
in \( y=x \)
Range
domain of \( f^{-1} \)
Worked example 8.A

If \( f(x)=3x-2 \), find \( f^{-1}(x) \).

\[ f^{-1}(x)=\frac{x+2}{3}. \]

Worked example — Composite functions

Given \(f(x)=\sqrt{x+1}\) (\(x\geq-1\)) and \(g(x)=2x-3\), find (a) \(fg(x)\), (b) the range of \(fg\).

(a) \(fg(x)=f(2x-3)=\sqrt{2x-3+1}=\sqrt{2x-2}\), domain \(x\geq1\).

(b) As \(x\geq1\), \(2x-2\geq0\), so range of \(fg\) is \(fg(x)\geq0\).

\(f(x)=3x-5\). Find (a) \(f^{-1}(x)\), (b) \(ff(2)\).
(a) \(y=3x-5\Rightarrow x=\tfrac{y+5}{3}\). So \(f^{-1}(x)=\tfrac{x+5}{3}\). (b) \(f(2)=1\); \(ff(2)=f(1)=-2\).
📝 Chapter Quiz
9

Circular Measure

📌 Circular Measure P1  ·  Radians ↔ degrees  ·  Arc length \(s=r\theta\)  ·  Sector area \(A=\tfrac{1}{2}r^2\theta\)  ·  Segment area

Angles measured in radians give clean formulas for arc length and sector area.

▲ Reference — Radians

\( 180^{\circ}=\pi \) radians. Arc length \( s=r\theta \); sector area \( A=\tfrac12 r^{2}\theta \), with \( \theta \) in radians.

Convert
\( 180^{\circ}=\pi \)
Arc length
\( s=r\theta \)
Sector
\( \tfrac12 r^{2}\theta \)
Full turn
\( 2\pi \)
Worked example 9.A

Find the arc length when \( r=5 \) and \( \theta=\tfrac{\pi}{3} \).

\[ s=5\cdot\frac{\pi}{3}=\frac{5\pi}{3}. \]

Worked example — Segment area

A sector OAB has radius 8 cm and angle \(\angle AOB=1.2\) rad. Find the area of the minor segment cut off by chord AB.

\[\text{Sector area}=\tfrac{1}{2}(8)^2(1.2)=38.4\text{ cm}^2.\]\[\text{Triangle area}=\tfrac{1}{2}(8)^2\sin(1.2)=32\sin(1.2)\approx29.56\text{ cm}^2.\]\[\text{Segment}=38.4-29.56\approx8.84\text{ cm}^2.\]

The area of a sector is \(54\) cm² and its radius is 6 cm. Find the arc length.
Area \(=\tfrac{1}{2}r^2\theta\Rightarrow54=18\theta\Rightarrow\theta=3\) rad. Arc \(=r\theta=6\times3=18\) cm.
📝 Chapter Quiz
10

Series & the Binomial Theorem

📌 Series & Binomial Theorem P1  ·  AP & GP formulas  ·  Sum to infinity  ·  \((a+b)^n\) expansion  ·  General term

Arithmetic and geometric progressions, and the binomial expansion of \( (a+b)^{n} \).

▲ Reference — Series

AP sum \( S_n=\tfrac{n}{2}\big(2a+(n-1)d\big) \); GP sum \( S_n=\tfrac{a(1-r^{n})}{1-r} \); binomial \( (1+x)^{n}=1+nx+\tfrac{n(n-1)}{2}x^{2}+\cdots \).

AP term
\( a+(n-1)d \)
AP sum
\( \tfrac{n}{2}(2a+(n-1)d) \)
GP sum
\( \tfrac{a(1-r^{n})}{1-r} \)
Binomial
\( {}^nC_r \)
Worked example 10.A

Find the sum of the first \( 10 \) terms of \( 2,5,8,\dots \)

\[ S_{10}=\frac{10}{2}\big(4+27\big)=155. \]

Worked example — Geometric series & sum to infinity

A geometric series has first term 12 and common ratio \(\tfrac{2}{3}\). Find (a) the 5th term, (b) \(S_\infty\).

(a) \(u_5=12\cdot(\tfrac{2}{3})^4=12\cdot\tfrac{16}{81}=\tfrac{64}{27}\).

(b) \(S_\infty=\dfrac{12}{1-\tfrac{2}{3}}=\dfrac{12}{\tfrac{1}{3}}=36\).

Find the coefficient of \(x^3\) in the expansion of \((2+x)^7\).
\(\binom{7}{3}(2)^4(x)^3=35\times16\times x^3=560x^3\). Coefficient is \(560\).
📝 Chapter Quiz
11

Kinematics

📌 Kinematics M1  ·  SUVAT equations  ·  Velocity–time graphs  ·  Calculus kinematics

Mechanics begins with motion in a straight line under constant acceleration.

▲ Reference — suvat equations

For constant acceleration: \( v=u+at \), \( s=ut+\tfrac12 at^{2} \), \( v^{2}=u^{2}+2as \). Velocity is the derivative of displacement; acceleration the derivative of velocity.

Velocity
\( v=u+at \)
Displacement
\( ut+\tfrac12at^{2} \)
No time
\( v^{2}=u^{2}+2as \)
Acceleration
\( \tfrac{dv}{dt} \)
Worked example 11.A

With \( u=0 \), \( a=2 \), \( t=3 \), find \( v \).

\[ v=0+2(3)=6. \]

Worked example — Calculus kinematics

A particle moves so that its velocity at time \(t\) s is \(v=3t^2-12t+9\) m/s. Find (a) the acceleration at \(t=2\), (b) when the particle is momentarily at rest.

(a) \(a=\dfrac{dv}{dt}=6t-12\). At \(t=2\): \(a=0\) m/s².

(b) \(v=0\Rightarrow3(t-1)(t-3)=0\Rightarrow t=1\) s or \(t=3\) s.

A car decelerates uniformly from 25 m/s to rest in 10 s. Find (a) the deceleration, (b) the distance travelled.
SUVAT: \(u=25\), \(v=0\), \(t=10\). (a) \(a=\tfrac{v-u}{t}=\tfrac{-25}{10}=-2.5\) m/s². (b) \(s=\tfrac{u+v}{2}t=\tfrac{25}{2}\times10=125\) m.
📝 Chapter Quiz
12

Forces & Equilibrium

📌 Forces & Equilibrium M1  ·  Resultant force  ·  Resolving into components  ·  Lami's theorem  ·  Friction \(F=\mu R\)

Types of Forces

Weight \(W=mg\), Normal reaction \(N\), Tension \(T\), Friction \(F\leq\mu N\). Forces are vectors — resolve horizontally and vertically.

Equilibrium

A particle is in equilibrium when the resultant force is zero: \(\sum F_x=0\) and \(\sum F_y=0\). Use triangle/polygon of forces.

Resolving Forces

Force \(F\) at angle \(\theta\): horizontal component \(F\cos\theta\), vertical component \(F\sin\theta\).

Friction

Limiting friction: \(F=\mu N\). When moving: \(F=\mu N\). Static: \(F\leq\mu N\). \(\mu\) is the coefficient of friction.

Lami's Theorem

For three concurrent forces in equilibrium: \(\dfrac{F_1}{\sin\alpha}=\dfrac{F_2}{\sin\beta}=\dfrac{F_3}{\sin\gamma}\)

Inclined Planes

On slope at angle \(\alpha\): component along slope \(=mg\sin\alpha\), perpendicular \(=mg\cos\alpha\).

▲ Forces & Equilibrium — Reference

A force is a vector (magnitude + direction). The resultant of forces is found by vector addition; for equilibrium the resultant is zero. Resolve forces into horizontal and vertical components: \(F_x=F\cos\theta\), \(F_y=F\sin\theta\). Friction force satisfies \(F\leq\mu R\); limiting equilibrium: \(F=\mu R\).

Resolving
\(F_x=F\cos\theta,\quad F_y=F\sin\theta\)
Equilibrium
\(\sum F_x=0\quad\&\quad\sum F_y=0\)
Friction (limiting)
\(F=\mu R\)
Resultant
\(R=\sqrt{F_x^2+F_y^2}\)
Worked example — Resolving forces in equilibrium

A particle is in equilibrium under three forces: 10 N acting due East, 8 N acting due North, and a third force \(F\). Find the magnitude and direction of \(F\).

For equilibrium: \(F_x=-10\) N, \(F_y=-8\) N.

\[|F|=\sqrt{100+64}=\sqrt{164}\approx12.8\text{ N},\quad\tan\theta=\frac{8}{10}\Rightarrow\theta=38.7°\text{ W of S}.\]

Worked example — Friction on an inclined plane

A block of mass 5 kg lies on a rough plane inclined at 30° to the horizontal (\(\mu=0.4\), \(g=10\) m/s²). Find the friction force acting when the block is on the point of sliding down.

Normal reaction: \(R=5g\cos30°=50\times\tfrac{\sqrt3}{2}\approx43.3\) N.

Friction (limiting, up the slope): \(F=0.4\times43.3\approx17.3\) N.

Check: Gravity component down slope \(=50\sin30°=25\) N \(>F\), so block would slide — friction acts up slope.

A particle of weight 20 N is in equilibrium on a smooth plane inclined at 40° to the horizontal, held by a string parallel to the plane. Find the tension \(T\) in the string and the normal reaction \(R\).
\(T=20\sin40°\approx12.9\) N. \(R=20\cos40°\approx15.3\) N.
13

Newton's Laws of Motion

📌 Newton's Laws of Motion M1  ·  \(F=ma\)  ·  Connected particles & pulleys  ·  Tension & reaction forces

Newton's First Law

A body remains at rest or in uniform motion unless acted upon by a resultant force. Inertia.

Newton's Second Law

\(F=ma\) where \(F\) is resultant force (N), \(m\) is mass (kg), \(a\) is acceleration (m/s²).

Newton's Third Law

For every action there is an equal and opposite reaction. Forces occur in equal pairs on different bodies.

Connected Particles

Particles connected by strings over pulleys: apply \(F=ma\) to each particle separately, then solve simultaneously.

Acceleration on Slopes

Net force along slope \(=mg\sin\alpha - F_{friction}\). Apply \(F=ma\) to find acceleration.

Momentum

Momentum \(p=mv\). Newton's 2nd law: \(F=\dfrac{d(mv)}{dt}\). Conservation: \(m_1u_1+m_2u_2=m_1v_1+m_2v_2\).

▲ Newton's Laws — Reference

N1: A body remains at rest or in uniform motion unless acted on by a net force. N2: \(F=ma\) (net force = mass × acceleration). N3: For every action there is an equal and opposite reaction. For connected particles (e.g. Atwood's machine), consider each particle separately; the tension \(T\) is the same throughout an inextensible string over a smooth pulley.

Newton's 2nd Law
\(F_\text{net}=ma\)
Atwood's machine
\(a=\dfrac{(m_1-m_2)g}{m_1+m_2}\)
Tension (same string)
Same \(T\) throughout
Weight
\(W=mg\)
Worked example — Single particle on a surface

A force of 30 N acts on a 6 kg box on a rough horizontal surface (\(\mu=0.3\), \(g=10\) m/s²). Find the acceleration.

\[R=mg=60\text{ N},\quad F_\text{friction}=0.3\times60=18\text{ N}.\]\[F_\text{net}=30-18=12\text{ N},\quad a=\frac{12}{6}=2\text{ m/s}^2.\]

Worked example — Connected particles over a pulley

Two particles of mass 4 kg and 6 kg are connected by a light inextensible string over a smooth pulley. Find the acceleration and the tension in the string (\(g=10\) m/s²).

Taking down as positive for the 6 kg particle:

\[6g-T=6a,\quad T-4g=4a.\]\[\text{Adding: }2g=10a\Rightarrow a=2\text{ m/s}^2,\quad T=4(10+2)=48\text{ N}.\]

A car of mass 1200 kg experiences a driving force of 3600 N and a resistance of 800 N. Find the acceleration. If the car then cuts the engine, find the deceleration.
Acceleration: \(F_\text{net}=3600-800=2800\) N, \(a=2800/1200\approx2.33\) m/s². Deceleration: \(F_\text{net}=-800\) N, \(a=-800/1200\approx-0.667\) m/s².
14

Energy, Work & Power

📌 Energy, Work & Power M1  ·  Kinetic energy  ·  Gravitational PE  ·  Work-energy principle  ·  Power \(P=Fv\)

Work Done

\(W=Fd\cos\theta\) where \(F\) is force, \(d\) distance, \(\theta\) angle between force and displacement. Units: Joules (J).

Kinetic Energy

\(KE=\tfrac{1}{2}mv^2\). Work-energy theorem: \(W_{net}=\Delta KE=\tfrac{1}{2}mv^2-\tfrac{1}{2}mu^2\).

Potential Energy

Gravitational PE: \(GPE=mgh\). Change in GPE: \(\Delta GPE=mg\Delta h\).

Conservation of Energy

\(KE+PE=\text{constant}\) (no friction). With friction: \(\Delta KE+\Delta PE+W_{friction}=0\).

Power

\(P=\dfrac{W}{t}=Fv\). Units: Watts (W). Maximum speed when driving force = resistance: \(P=F_{resistance}\cdot v_{max}\).

Efficiency

\(\text{efficiency}=\dfrac{\text{useful power output}}{\text{power input}}\times100\%\)

▲ Energy, Work & Power — Reference

Kinetic energy: \(\text{KE}=\tfrac{1}{2}mv^2\). Gravitational PE: \(\text{GPE}=mgh\). Work-energy principle: net work done = change in KE. Work done by a force: \(W=Fd\cos\theta\). Power: \(P=\dfrac{W}{t}=Fv\). Conservation of energy: \(\text{KE}_1+\text{GPE}_1=\text{KE}_2+\text{GPE}_2\) (no friction).

Kinetic energy
\(\tfrac{1}{2}mv^2\)
Gravitational PE
\(mgh\)
Work done
\(Fd\cos\theta\)
Power
\(P=Fv\)
Worked example — Work-energy principle

A 2 kg ball rolls down a smooth slope of height 5 m from rest. Find its speed at the bottom (\(g=10\) m/s²).

\[\text{Loss in GPE}=\text{Gain in KE}:\quad2\times10\times5=\tfrac{1}{2}\times2\times v^2\Rightarrow v^2=100\Rightarrow v=10\text{ m/s}.\]

Worked example — Power

A car of mass 900 kg moves at constant speed 30 m/s against a resistance of 500 N. Find the power output of the engine.

At constant speed, driving force = resistance = 500 N.

\[P=Fv=500\times30=15\,000\text{ W}=15\text{ kW}.\]

A 3 kg block slides 4 m down a rough slope inclined at 30°. The friction force is 8 N. Find the speed at the bottom if it starts from rest (\(g=10\) m/s²).
Work by gravity: \(W_g=3\times10\times4\sin30°=60\) J. Work by friction: \(W_f=-8\times4=-32\) J. Net work \(=28\) J. \(\tfrac{1}{2}(3)v^2=28\Rightarrow v^2=\tfrac{56}{3}\Rightarrow v\approx4.32\) m/s.
🔗 See also: Forces · Newton's Laws
15

Representation of Data

📌 Representation of Data S1  ·  Histograms & frequency density  ·  Cumulative frequency  ·  Mean, variance & SD  ·  Box-and-whisker plots

Stem-and-Leaf Diagrams

Display raw data in order. Back-to-back stem plots compare two datasets. Median and quartiles easy to read.

Box-and-Whisker Plots

Shows minimum, Q1, median, Q3, maximum. IQR = Q3 − Q1. Outliers: values outside \(Q_1-1.5\times IQR\) or \(Q_3+1.5\times IQR\).

Histograms

Frequency density = frequency ÷ class width. Area of bar represents frequency. Used for continuous grouped data.

Cumulative Frequency

Ogive (cumulative frequency curve). Read median at \(n/2\), Q1 at \(n/4\), Q3 at \(3n/4\).

Measures of Location

Mean \(\bar{x}=\dfrac{\sum fx}{\sum f}\), Median (middle value), Mode (most frequent). For grouped data use midpoint.

Measures of Spread

Range, IQR, Variance \(\sigma^2=\dfrac{\sum fx^2}{n}-\bar{x}^2\), Standard deviation \(\sigma\).

▲ Representation of Data — Reference

For grouped data with \(n\) values: mean \(\bar{x}=\dfrac{\sum fx}{\sum f}\); variance \(\sigma^2=\dfrac{\sum fx^2}{\sum f}-\bar{x}^2\); standard deviation \(\sigma=\sqrt{\text{Var}}\). In a histogram (unequal class widths), plot frequency density \(=\text{freq}/\text{class width}\). In a cumulative frequency graph, the median is the \(\tfrac{n}{2}\)th value, \(Q_1\) is the \(\tfrac{n}{4}\)th, \(Q_3\) is the \(\tfrac{3n}{4}\)th.

Mean (grouped)
\(\bar{x}=\dfrac{\sum fx}{\sum f}\)
Variance
\(\dfrac{\sum fx^2}{\sum f}-\bar{x}^2\)
Freq. density
freq ÷ class width
IQR
\(Q_3-Q_1\)
Worked example — Mean and variance from table

Scores: 1 (freq 2), 2 (freq 5), 3 (freq 8), 4 (freq 3), 5 (freq 2). Find the mean and standard deviation.

\(\sum f=20\), \(\sum fx=2+10+24+12+10=58\). Mean \(=58/20=2.9\).

\(\sum fx^2=2+20+72+48+50=192\). Var \(=192/20-2.9^2=9.6-8.41=1.19\). SD \(\approx1.09\).

Worked example — Cumulative frequency

Data range 0–50. Cumulative frequencies at 10,20,30,40,50 are 5,18,34,44,50. Estimate the median and IQR.

Median at \(n/2=25\)th value: read from cf graph at cf=25 → \(\approx27\). \(Q_1\) at cf=12.5 → \(\approx18\). \(Q_3\) at cf=37.5 → \(\approx33\). IQR\(\approx15\).

A data set has mean 12 and standard deviation 4. A new value of 20 is added to \(n=9\) existing values. Without finding the new variance, find the new mean.
Old sum \(=9\times12=108\). New sum \(=108+20=128\). New mean \(=128/10=12.8\).
16

Permutations & Combinations

📌 Permutations & Combinations S1  ·  Factorial  ·  \(^nP_r\)  ·  \(^nC_r\)  ·  Arrangements with identical items or restrictions

Factorial

\(n! = n\times(n-1)\times\cdots\times2\times1\). Convention: \(0!=1\).

Permutations

Ordered arrangements: \(^nP_r=\dfrac{n!}{(n-r)!}\). Order matters. \(n\) objects in a line: \(n!\) ways.

Combinations

Unordered selections: \(^nC_r=\dbinom{n}{r}=\dfrac{n!}{r!(n-r)!}\). Order does not matter.

Restrictions

Always together: treat as one unit, then \((n-1)!\times r!\). Never together: total − (always together).

Circular Arrangements

\((n-1)!\) ways to arrange \(n\) objects in a circle (one position is fixed).

Identical Objects

Arrangements of \(n\) objects with repeats: \(\dfrac{n!}{a!\,b!\,c!\cdots}\)

▲ Permutations & Combinations — Reference

Permutation (order matters): \(^nP_r=\dfrac{n!}{(n-r)!}\). Combination (order does not matter): \(^nC_r=\dbinom{n}{r}=\dfrac{n!}{r!\,(n-r)!}\). Arrangements with identical items: divide by the factorial of each repeated item. With restrictions: fix the restricted items first, then arrange the rest.

Permutation
\(^nP_r=\dfrac{n!}{(n-r)!}\)
Combination
\(^nC_r=\dfrac{n!}{r!(n-r)!}\)
Identical items
\(\dfrac{n!}{a!\,b!\cdots}\)
Fix & arrange
Fix restricted → count rest
Worked example — Combinations with restrictions

A committee of 4 is chosen from 5 men and 6 women. Find the number of ways if the committee must contain at least 2 women.

Exactly 2W: \(\binom{6}{2}\binom{5}{2}=15\times10=150\). Exactly 3W: \(\binom{6}{3}\binom{5}{1}=20\times5=100\). Exactly 4W: \(\binom{6}{4}\binom{5}{0}=15\). Total: \(265\).

Worked example — Arrangements of letters

How many different arrangements are there of the letters of the word BANANA?

6 letters; N appears 2 times, A appears 3 times: \(\dfrac{6!}{3!\,2!}=\dfrac{720}{12}=60\).

In how many ways can 5 people be seated in a row if two particular people (A and B) must not sit next to each other?
Total \(=5!=120\). Cases where A & B are adjacent: treat AB as a block → \(4!\times2=48\). Answer: \(120-48=72\).
🔗 See also: Binomial Distribution
17

Discrete Random Variables

📌 Discrete Random Variables S1  ·  Probability distribution table  ·  \(E(X)\)  ·  \(\text{Var}(X)\)  ·  Linear transforms \(E(aX+b)\)

Probability Distribution

Table of \(x\) values and corresponding \(P(X=x)\). Must satisfy: \(\sum P(X=x)=1\) and \(P(X=x)\geq0\).

Expectation

\(E(X)=\sum x\cdot P(X=x)=\mu\). Also \(E(aX+b)=aE(X)+b\).

Variance

\(\text{Var}(X)=E(X^2)-[E(X)]^2\) where \(E(X^2)=\sum x^2P(X=x)\). Also \(\text{Var}(aX+b)=a^2\text{Var}(X)\).

Standard Deviation

\(\sigma=\sqrt{\text{Var}(X)}\). Measures spread around the mean.

Uniform Distribution

Each value equally likely. If \(X\) takes values \(1,2,\ldots,n\): \(E(X)=\dfrac{n+1}{2}\), \(\text{Var}(X)=\dfrac{n^2-1}{12}\).

Combined Variables

\(E(X+Y)=E(X)+E(Y)\). If independent: \(\text{Var}(X+Y)=\text{Var}(X)+\text{Var}(Y)\).

▲ Discrete Random Variables — Reference

A discrete random variable \(X\) has a probability distribution with \(\sum P(X=x)=1\). Expectation: \(E(X)=\sum x\,P(X=x)\). Variance: \(\text{Var}(X)=E(X^2)-[E(X)]^2\) where \(E(X^2)=\sum x^2 P(X=x)\). For linear transforms: \(E(aX+b)=aE(X)+b\); \(\text{Var}(aX+b)=a^2\text{Var}(X)\).

E(X)
\(\sum x\,P(X=x)\)
Var(X)
\(E(X^2)-[E(X)]^2\)
E(aX+b)
\(aE(X)+b\)
Var(aX+b)
\(a^2\text{Var}(X)\)
Worked example — Finding E(X) and Var(X)

A biased die shows: \(P(1)=0.1,P(2)=0.2,P(3)=0.3,P(4)=0.3,P(5)=0.1\). Find \(E(X)\) and \(\text{Var}(X)\).

\[E(X)=0.1(1)+0.2(2)+0.3(3)+0.3(4)+0.1(5)=0.1+0.4+0.9+1.2+0.5=3.1.\]\[E(X^2)=0.1(1)+0.2(4)+0.3(9)+0.3(16)+0.1(25)=0.1+0.8+2.7+4.8+2.5=10.9.\]\[\text{Var}(X)=10.9-3.1^2=10.9-9.61=1.29.\]

Worked example — Unknown probability

\(X\) takes values 0, 1, 2 with \(P(X=0)=k\), \(P(X=1)=2k\), \(P(X=2)=3k\). Find \(k\) and \(E(X)\).

\[k+2k+3k=1\Rightarrow k=\tfrac{1}{6}.\quad E(X)=0\cdot\tfrac{1}{6}+1\cdot\tfrac{2}{6}+2\cdot\tfrac{3}{6}=\tfrac{8}{6}=\tfrac{4}{3}.\]

\(E(X)=3\) and \(\text{Var}(X)=2\). Find \(E(3X-1)\) and \(\text{Var}(3X-1)\).
\(E(3X-1)=3(3)-1=8\). \(\text{Var}(3X-1)=9\times2=18\).
18

Binomial Distribution

📌 Binomial Distribution S1  ·  \(X\sim B(n,p)\)  ·  \(P(X=r)=\binom{n}{r}p^r(1-p)^{n-r}\)  ·  Mean \(np\)  ·  Variance \(np(1-p)\)

Conditions

Fixed number of trials \(n\); each trial has two outcomes (success/failure); constant probability \(p\); trials independent. Then \(X\sim B(n,p)\).

Probability Formula

\(P(X=r)=\dbinom{n}{r}p^r(1-p)^{n-r}\) for \(r=0,1,2,\ldots,n\).

Mean and Variance

\(E(X)=np\), \(\text{Var}(X)=np(1-p)\), \(\sigma=\sqrt{np(1-p)}\).

Cumulative Probabilities

Use tables or calculator: \(P(X\leq r)\). Note: \(P(X\geq r)=1-P(X\leq r-1)\).

Normal Approximation

If \(n\) large and \(p\) close to 0.5: \(X\approx N(np,\,np(1-p))\) with continuity correction.

Finding Unknown n or p

Set up equations using given probabilities and solve. May require trial and error or logarithms for \(n\).

▲ Binomial Distribution — Reference

If \(X\sim B(n,p)\): \(n\) independent trials, each with probability \(p\) of success. \(P(X=r)=\dbinom{n}{r}p^r(1-p)^{n-r}\). Mean: \(E(X)=np\). Variance: \(\text{Var}(X)=np(1-p)\). Use the binomial distribution when: fixed \(n\), trials independent, constant \(p\), only 2 outcomes (success/failure).

\(P(X=r)\)
\(\binom{n}{r}p^r(1-p)^{n-r}\)
Mean
\(np\)
Variance
\(np(1-p)\)
Conditions
Fixed \(n\), independent, constant \(p\)
Worked example — Exact probability

\(X\sim B(8,0.3)\). Find (a) \(P(X=3)\), (b) \(P(X\leq1)\).

(a) \(P(X=3)=\binom{8}{3}(0.3)^3(0.7)^5=56\times0.027\times0.16807\approx0.2541\).

(b) \(P(X=0)=(0.7)^8\approx0.0576\); \(P(X=1)=8(0.3)(0.7)^7\approx0.1977\). \(P(X\leq1)\approx0.2553\).

Worked example — Finding n from mean

The mean of \(X\sim B(n,0.4)\) is 6. Find \(n\) and the standard deviation.

\[np=6\Rightarrow n=15.\quad\sigma=\sqrt{15\times0.4\times0.6}=\sqrt{3.6}\approx1.90.\]

A fair coin is tossed 10 times. Find the probability of getting (a) exactly 6 heads, (b) fewer than 3 heads.
(a) \(\binom{10}{6}(0.5)^{10}=210\times\tfrac{1}{1024}\approx0.2051\). (b) \(P(X\leq2)=P(0)+P(1)+P(2)=\tfrac{1+10+45}{1024}=\tfrac{56}{1024}\approx0.0547\).
19

Normal Distribution

📌 Normal Distribution S1  ·  \(X\sim N(\mu,\sigma^2)\)  ·  Standardising \(Z=\tfrac{X-\mu}{\sigma}\)  ·  Tables & symmetry  ·  Finding \(\mu\) or \(\sigma\)

The Normal Curve

Bell-shaped, symmetric about mean \(\mu\). \(X\sim N(\mu,\sigma^2)\). Approximately 68%/95%/99.7% within 1/2/3 standard deviations.

Standardising

\(Z=\dfrac{X-\mu}{\sigma}\sim N(0,1)\). Use \(Z\)-tables (standard normal) to find probabilities.

Finding Probabilities

\(P(X<a)=\Phi\!\left(\dfrac{a-\mu}{\sigma}\right)\). Use symmetry: \(P(Z<-z)=1-P(Z<z)\).

Inverse Normal

Given probability, find the value. \(P(X<a)=p\Rightarrow a=\mu+z\sigma\) where \(z=\Phi^{-1}(p)\).

Finding μ or σ

Set up two equations from given probabilities, solve simultaneously for unknown parameters.

Normal Approximation

To Binomial \(B(n,p)\): if \(n\) large, \(np>5\), \(n(1-p)>5\): use \(N(np,np(1-p))\) with continuity correction \(\pm0.5\).

▲ Normal Distribution — Reference

If \(X\sim N(\mu,\sigma^2)\): standardise with \(Z=\dfrac{X-\mu}{\sigma}\) where \(Z\sim N(0,1)\). Use tables (or calculator) for \(\Phi(z)=P(Z\leq z)\). Key symmetry: \(P(Z\leq -z)=1-P(Z\leq z)\). For inverse normal: given a probability, find the corresponding \(x\) value using \(x=\mu+z\sigma\).

Standardise
\(Z=\dfrac{X-\mu}{\sigma}\)
Symmetry
\(P(Z\leq-z)=1-\Phi(z)\)
Inverse normal
\(x=\mu+z\sigma\)
Normal approx to B
Use when \(n\) large, \(p\approx0.5\)
Worked example — Finding a probability

\(X\sim N(50,16)\) so \(\sigma=4\). Find \(P(44\leq X\leq58)\).

\[P\!\left(\frac{44-50}{4}\leq Z\leq\frac{58-50}{4}\right)=P(-1.5\leq Z\leq 2)=\Phi(2)-\Phi(-1.5).\]\[=0.9772-(1-0.9332)=0.9772-0.0668=0.9104.\]

Worked example — Finding \(\mu\)

\(X\sim N(\mu,25)\). Given \(P(X>43)=0.2119\), find \(\mu\).

\(P(Z>\tfrac{43-\mu}{5})=0.2119\Rightarrow\tfrac{43-\mu}{5}=0.8\) (from tables). \(\mu=43-4=39\).

\(X\sim N(30,\sigma^2)\) and \(P(X<25)=0.0668\). Find \(\sigma\).
\(P(Z<\tfrac{25-30}{\sigma})=0.0668\Rightarrow\tfrac{-5}{\sigma}=-1.5\Rightarrow\sigma=\tfrac{5}{1.5}\approx3.33\).
§

Practice set

Fifty AS-style problems across the Pure core plus statistics, tagged by difficulty. Click any problem for a full worked solution.

1

Simplify \( x^{3}\cdot x^{4} \).

Basic
\[ x^{7}. \]
2

Evaluate \( 2^{-3} \).

Intermediate
\[ \frac{1}{2^{3}}=\tfrac{1}{8}. \]
3

Simplify \( \sqrt{12} \).

Intermediate
\[ \sqrt{4\cdot3}=2\sqrt{3}. \]
4

Rationalise \( \dfrac{1}{\sqrt{2}} \).

Advanced

Multiply by \( \tfrac{\sqrt2}{\sqrt2} \):

\[ \tfrac{\sqrt{2}}{2}. \]
5

Simplify \( (x^{2})^{5} \).

Intermediate
\[ x^{10}. \]
6

Evaluate \( 27^{1/3} \).

Advanced
\[ \sqrt[3]{27}=3. \]
7

Solve \( x^{2}=16 \).

Basic
\[ x=\pm4. \]
8

Factor \( x^{2}+5x+6 \).

Intermediate
\[ (x+2)(x+3). \]
9

Solve \( x^{2}-6x+8=0 \).

Intermediate

\( (x-2)(x-4)=0 \):

\[ x=2,\ 4. \]
10

Complete the square for \( x^{2}+4x \).

Intermediate
\[ (x+2)^{2}-4. \]
11

How many real roots does \( x^{2}+x+1=0 \) have?

Advanced

Discriminant \( =1-4=-3<0 \):

\[ \text{none.} \]
12

Find the sum of the roots of \( x^{2}-5x+6=0 \).

Intermediate
\[ 2+3=5. \]
13

Solve \( 2x^{2}-5x-3=0 \).

Advanced

\( (2x+1)(x-3)=0 \):

\[ x=3,\ -\tfrac12. \]
14

Find the vertex of \( y=x^{2}-4x+3 \).

Intermediate

\( (x-2)^{2}-1 \):

\[ (2,\,-1). \]
15

Solve \( x+y=5 \), \( x-y=1 \).

Intermediate

Add: \( 2x=6 \):

\[ x=3,\ y=2. \]
16

Solve \( 2x+y=8 \), \( y=x-1 \).

Intermediate

\( 2x+x-1=8 \Rightarrow x=3 \):

\[ x=3,\ y=2. \]
17

Solve \( y=x^{2} \), \( y=x+2 \).

Advanced

\( x^{2}-x-2=0\Rightarrow(x-2)(x+1)=0 \):

\[ (2,4),\ (-1,1). \]
18

Solve \( 2x-3>5 \).

Intermediate

\( 2x>8 \):

\[ x>4. \]
19

Solve \( 3x+1\le10 \).

Intermediate

\( 3x\le9 \):

\[ x\le3. \]
20

Solve \( x^{2}-4<0 \).

Advanced
\[ -2<x<2. \]
21

Find the gradient through \( (1,2) \) and \( (4,11) \).

Intermediate
\[ \frac{11-2}{4-1}=3. \]
22

Find the midpoint of \( (2,3) \) and \( (8,7) \).

Intermediate
\[ (5,\,5). \]
23

Find the equation of the line with gradient \( 2 \) through \( (1,3) \).

Advanced

\( y-3=2(x-1) \):

\[ y=2x+1. \]
24

Find the distance between \( (1,1) \) and \( (4,5) \).

Intermediate
\[ \sqrt{9+16}=5. \]
25

State the centre of \( (x-2)^{2}+(y+3)^{2}=25 \).

Advanced
\[ (2,\,-3). \]
26

State the radius of \( x^{2}+y^{2}=49 \).

Intermediate
\[ r=7. \]
27

Describe \( y=x^{2}+3 \) relative to \( y=x^{2} \).

Intermediate

A translation \( 3 \) units up.

28

Describe \( y=(x-2)^{2} \) relative to \( y=x^{2} \).

Intermediate

A translation \( 2 \) units to the right.

29

Describe \( y=-x^{2} \) relative to \( y=x^{2} \).

Advanced

A reflection in the \( x \)-axis.

30

How does \( y=f(x)+k \) transform the graph of \( y=f(x) \)?

Intermediate

A vertical translation by \( k \).

31

Evaluate \( \sin30^{\circ} \).

Intermediate
\[ \tfrac12. \]
32

Evaluate \( \cos0^{\circ} \).

Intermediate
\[ 1. \]
33

Evaluate \( \tan45^{\circ} \).

Intermediate
\[ 1. \]
34

Solve \( \sin\theta=\tfrac12 \) for \( 0^{\circ}\le\theta\le180^{\circ} \).

Advanced
\[ \theta=30^{\circ},\ 150^{\circ}. \]
35

Simplify \( \sin^{2}\theta+\cos^{2}\theta \).

Intermediate
\[ 1. \]
36

State the exact value of \( \sin60^{\circ} \).

Advanced
\[ \tfrac{\sqrt{3}}{2}. \]
37

Evaluate \( \cos90^{\circ} \).

Intermediate
\[ 0. \]
38

State the period of \( y=\sin x \).

Advanced
\[ 360^{\circ}. \]
39

Differentiate \( x^{2} \).

Intermediate
\[ 2x. \]
40

Differentiate \( x^{3} \).

Intermediate
\[ 3x^{2}. \]
41

Differentiate \( 5x \).

Intermediate
\[ 5. \]
42

Find \( \dfrac{dy}{dx} \) for \( y=x^{2}+3x \).

Advanced
\[ 2x+3. \]
43

Find \( \displaystyle\int 2x\,dx \).

Intermediate
\[ x^{2}+C. \]
44

Find \( \displaystyle\int x^{2}\,dx \).

Advanced
\[ \tfrac{x^{3}}{3}+C. \]
45

Find the gradient of \( y=x^{2} \) at \( x=3 \).

Intermediate

\( \tfrac{dy}{dx}=2x=6 \):

\[ 6. \]
46

Evaluate \( \displaystyle\int_{0}^{1} 2x\,dx \).

Advanced
\[ \left[x^{2}\right]_{0}^{1}=1. \]
47

Find the mean of \( 2,\,4,\,6,\,8 \).

Intermediate
\[ \frac{20}{4}=5. \]
48

Find the median of \( 3,\,7,\,9,\,12,\,20 \).

Intermediate
\[ 9. \]
49

A fair die is rolled. Find \( P(\text{even}) \).

Advanced
\[ \tfrac{3}{6}=\tfrac12. \]
50

Find the range of \( 5,\,9,\,2,\,11 \).

Intermediate
\[ 11-2=9. \]

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